College Algebra
posted by Anonymous .
Find the average rate of change for function f(x)=3x^(2)5 at the points x[1]=6 and x[2]=10

avg rate of change is ∆y/∆x for the interval
∆y = f(10)f(6) = 295103 = 192
∆x = 106 = 4
avg rate of change is thus 192/4 = 48
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