posted by Paul .
Find to find equation of the tangent line y=x^4-x^3-x^2-x+1 at the point x=1
Is the calculus?
If so, take the derivative of y which would be 4x^3 - 3x^2-2x -1
Let x =1 to find the slope
4-3-2-1 = m = -2
find the value of y when x = 1
You will then have the slope and a point to use to find the equation using y=mx+b
so i found the y=-1
then i subbed into y=mx+b and got -1=-2(1)+b
then my equation would be -1=-2(1)+1
is that right?