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Oxygen gas and water are produced by the decomposition of hydrogen peroxide. If 10.0 mol of H2O2 decomposes, what volume of oxygen will be produced? Assume the density of oxygen is 1.429g/L. 2H2O2= 2H2O+O2

  • chem -

    2H2O2 ==> 2H2O + O2
    mol H2O2 = 10.0
    mol O2 produced = (1/2) x mols H2O2 = 1/2 x 10 = 5 mol
    At STP each mol will occupy 22.4 L.

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    lol

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