Mathematics
posted by Zico johnny .
Linear inequality, 2x+6 < 5(x3)

2x+6 < 5(x3) distribute 5 into x3
2x+6 < 5x15 move all x to one side
6 < 5x152x simplify
6 < 3x15 move 15 to other side
6+15 < 3x simplify
21 < 3x get x alone by dividing 3 on both sides
21/3 < 3x/3 simplify
7 < x and that's how you solve it. 
2x + 6 < 5x 15
Add 15 and subtract 2x from both sides.
21 < 3x
Divide both sides by 3.
7 < x
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