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a boat travels at 16 knots
1st leg: 6hr @ S63W
2nd leg: 4hr @ N10E
find time and bearing back to port

  • math -

    6hr @ S63W = 96@S63W = (-85.53,-43.58)
    4hr @ N10E = 64@N10E = (11.11,63.03)
    add them up to get (-74.42,19.45) = 76.92@N75W

    So,
    the bearing of the port on return is S75E.
    Time to port is 76.92/16 = 4.8 hr

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