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Let f(x)=x2+x−6x−2. Note that f(x) is undefined at x=2. However, in this case, we can find a continuous function g(x) defined at x=2 that agrees with f(x) near x=2. Find the function g(x) that is equal to f(x) when x≠2 such that

  • calculus -

    You must have a typo.
    I read your function as
    f(x) = x^2 - 5x - 2, which is defined for all values of x

    to be undefined there must have been a denominator of (x-2)

  • calculus -

    it's f(x)=x^2+x−6 / x−2
    and the answer is: x + 3

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