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solve the pair of equation for x and y respectively,2xpower-1 - 3y-1 equals 4 and 4xpower-1 + ypower-1 equals 1

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I will assume:
2x^-1 - 3y^-1 = 4 ---> 2/x - 3/y = 4
and
4x^-1 + y^-1 = 1 ----> 4/x + 1/y = 1

double the first : 4/x - 6/y = 8
keep the 2nd : 4/x + 1/y = 1
subtract them:
-7/y = 7
7y = -7
y = -1
back into the 2nd:
4/x + 1/-1 = 1
4/x = 2
2x = 4
x = 2

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