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algebra
this is what u do on your first problem....first u take out the greatest common factor that would go into all of them... 4n^220n+24...now what number will go into all of them...well 4 will...4 will go into 4,20,and 24...so. it would … 
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Shorten fraction: (x^2+2x)/(4x+8)= ? and reduce: (8a^3*b*a^2)/(2b)^2= ? 
math(one more time for today!)Please Help Belinda!
thanks,can you help me with this one: xy3x8y+24 I know you have to go, but you should be able to figure these out by now. Take out x from the first 2 and 8 from the second 2: x(y3)8(y3) (x8)(y3) acbc+adbd *I seriously only … 
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a^29 a^23a  *  a^2 a^2+a12 *I got: 33a/4 I don't think so. factor the a^29, and the second numerator to a(a3) Then the denominator factored is a^2*(a+4)(a3) So wait... don't I have to first have to take out the repeated … 
Simplifying Rational Expressions
1.4x12 / 4x 2.d+7 / d^249 3.t^225 / t^2+t20 4.2x^2+6x+4 / 4x^212x16 5.6y / y^22y24 1. 12 [4x] cancels out. so you're left with just 12. 2. 1/d7 factor the d^249 to (d+7)(d7). cancel out the (d+7) 3. (t5)/(t4) factor both … 
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Factor Completely: 3t^3 + 5t^2  12t first take out the t so you have: t(3t^2 + 5t  12) you should be able to factor it easily from there what numbers multiply to get (12 x 3) 36 and add to get 5? 
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how can i factor this out completly x^4+x^312 i know that4*3=12 but how can i get that middle term x^2*x^2=x^4 first you cannot take out any GCF. so if you decide to use grouping, you can create an equivalent problem: x^4 + x^3 … 
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factor 3a^2(ab)6a(ab)+21(ab) Can you show me the steps? 
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How do I factor these: 2x2  16x + 30 4x^29 x^25x 5x^226x+5 25x^2+4 Example: 2x^2  16x + 30 = 2 (x^2  8 x + 15) 2(x  5)(x  3) The first, factor out a 2 first. Then factor . The second...difference of two squares Third factor … 
MATH PLEASE HELP!!!
1.Factor 3/4 out of 3/4z+6. 2.Factor 18x+6y using the GCF. 3.Factor −5 out of −10a−25.