trigonometry

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A ship sails 15.0 mi on a course S40°10’W and then 21.0 mi on a course N28°20’W. Find the distance and direction of the last position from the first.

  • trigonometry -

    convert to (x,y) values and add:
    15@S40°10'W = (-9.675,-11.463)
    21@N28°20'W = (-9.967,18.484)
    sum = (-19.642,7.021)
    or,
    20.859@N70.33°W

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