trigonometry
posted by Mr.ask .
A ship sails 15.0 mi on a course S40°10’W and then 21.0 mi on a course N28°20’W. Find the distance and direction of the last position from the first.

convert to (x,y) values and add:
15@S40°10'W = (9.675,11.463)
21@N28°20'W = (9.967,18.484)
sum = (19.642,7.021)
or,
20.859@N70.33°W
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