math
posted by ifi .
solve lim (5000t^2)/ (t+2)^2.
the lim is t>infinity.
can someone show me the calculation. the ans is 5000.

limit ( 5000 t ^ 2) / ( t + 2 ) ^ 2 as t  > infinity =
5000 limit t ^ 2 / ( t + 2 ) ^ 2 as t  > infinity
________________________________________
t ^ 2 / ( t + 2 ) ^ 2
when t = infinity = infinity / infinity
so you must use L'Hospital's rule
________________________________________
5000 limit t ^ 2 / ( t + 2 ) ^ 2 as t  > infinity =
5000 limit [ d ( t ^ 2 / dt ) / d ( t + 2 ) ^ 2 / dt ] as t > infinity =
5000 limit [ t / ( t + 2 ) ] as t > infinity
________________________________________
5000 limit [ d ( t ) / dt / d ( t + 2 ) / dt ] as t > infinity =
5000 ( 1 / 1 ) = 5000
Respond to this Question
Similar Questions

Calc. Limits
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? 
calc
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? 
Calc Please Help
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? 
math
lim (76x^5)/(x+3).... the lim is x>+infinity [ans=infinity but i get 0] can someone show me the calculation work. 
math
lim (2x^2+3x2)/ (2x1) the lim is x>1/2 [ans:5/2 but i get 3/2) can someone show me the calculation work. 
math
i really don't understand why this 1lim 3/(y+4) [the lim is x>infinity] the ans is 0 while this 2lim (76x^5)/(x+3) [x>+infinity ] is  infinity. can anyone explain why the 1 is zero & the 2 is infinity. 
Calculus
Show that limit as n approaches infinity of (1+x/n)^n=e^x for any x>0... Should i use the formula e= lim as x>0 (1+x)^(1/x) or e= lim as x>infinity (1+1/n)^n Am i able to substitute in x/n for x? 
Math
1. If 1/infinity = infinity or infinity ? 
Math
1. If 1/infinity = infinity or infinity ? 
Math
Find the limit if it exists. lim 1/(x2) = infinity x→2+ lim 1/(x2) = negative infinity x→2 lim 1/(x2) = Does not exist x→2 lim (3x+2) = infinity x→∞ lim 999/(x^3) = 0 x→∞ Can someone check …