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Pre Calculus

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mx3-nx2+5x-1 is divided by x-2 the remainder is -39. When divided by x-1 the remainder is 3. What are the values of m and n. Didn't know how to do the superscript for mx3

  • Pre Calculus -

    use ^ for exponents

    using synthetic division, the remainders are:

    (x-2): 8m-4n+9
    (x-1): m-n+4

    so, we now know

    8m-4n+9 = -39
    m-n+4 = 3

    (m,n) = (-11,-10)

    f(x) = -11x^2 + 10x^2 + 5x - 1

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