# math

posted by .

completely factor

256z^2-4-192z^2+3

• math -

64z^2 - 1 => (8z-1)(8z+1)

## Similar Questions

1. ### Factor completely

I am to factor this completely and I am stuck. 2r^3 + 8r^2 +6r Note: x^2 is x-squared (that is, x with the superscript 2), etc. 2 is a factor and r is a factor so the equation becomes 2r(r^2 + 4r + 3) then we can factor the term in …
2. ### algebra

Completely factor the following expressions. 1. 256z^2-4-192z^2+3 2. 2a^2c^3-14bc^3+32c^3d^2 3. 35g^2+6g-9 4. 3j^3-51j^2+210j
3. ### algebra

Completely factor the following expressions. Please show work/explain t^2+4tv+4v2 4x^2-8x-12+6x 144-9p^2 5c^2-24cd-5d^2 w^2-17w+42 256z^2-4-192z^2+3 2a^2c^3-14bc^3+32c^3d^2 35g^2+6g-9 3j^3-51j^2+210j
4. ### math

I need help with these two problems please. Completely factor the polynomial. 8x^3+16^2+8x+16 Factor the trinomial completely. y^3-14y^2+48y

6. ### math help

Factor f(x) into linear factors given that k is a zero of f(x). f(x)=x^3+(12-4i)x^2+(32-48i)x-128i, k=4i In completely factored form, f(x) =____ (factor completely. simplify your answer)