Calculus

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intergrate 3x-4/x^2-4x+4

  • Calculus -

    I assume you mean
    (3x-4)dx/(x-2)^2

    3x dx/(x-2)^2 - 4 dx/(x-2)^2

    3[ -2/(x-2) + ln(x-2) ] -4 [ -1/(x-2) ]

    -6/(x-2) + 3 ln(x-2) + 4/(x-2)

    -2/(x-2) + 3 ln(x-2)

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