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posted by Anonymous Wednesday, December 19, 2012 at 12:25pm.
intergrate 3x-4/x^2-4x+4
I assume you mean (3x-4)dx/(x-2)^2 3x dx/(x-2)^2 - 4 dx/(x-2)^2 3[ -2/(x-2) + ln(x-2) ] -4 [ -1/(x-2) ] -6/(x-2) + 3 ln(x-2) + 4/(x-2) -2/(x-2) + 3 ln(x-2)
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