chemistry

posted by .

hey guys need some help here!!!
if 0.250mol of CO and 0.250mol of H2O were combined in a 125mL flask and the reaction allowed to reach equilibrium . Kc= 1.56. write the equ expression and calculate each substance

Co(g) +H2O(g) .... Co2(g) +H2(g)

  • math -

    how to work out (x)(x)
    -------- = 1.56
    ( 2-x)(2-x)

  • chemistry -

    ............CO + H2O ==> CO2 + H2
    I...........2....2........0.....0
    C...........-x...-x.......x.....x
    E...........2-x..2-x......x.....x

    Kc = (CO2)(H2)/(CO)(H2O)
    1.58 = (x)(x)/(2-x)(2-x)
    The right side is a perfect square so take the square root of each side.
    1.256 = (x)/(2-x)
    Solve for x

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    Write the equilibrium expression, and calculate Kp for the reaction under the conditions described: 2NaHCO3 (s) --> <--- Na2CO3 (s) + H2O (g) + CO2 (g) 100 g of solid NaHCO3 was placed in a previously evacuated rigid 5.00 L container …
  2. Chemistry

    Write the equilibrium expression, and calculate Kp for the reaction under the conditions described: 2NaHCO3 (s) --> <--- Na2CO3 (s) + H2O (g) + CO2 (g) 100 g of solid NaHCO3 was placed in a previously evacuated rigid 5.00 L container …
  3. Chemistry II

    The equlibrium constant Kc for the reaction: has the value of 4.00 at 500K. If a mixture of 1.00 mol CO and 1.00 mol H2O is allowed to reach equilibrium at this temperature in a 1.00L flask, calculate the equilibrium concentrations …
  4. chemistry check my work

    the equilibrium-constant expression for a reaction is kc= [N2][H2O]2 ---------- [NO]2[H2] what is the equilibrium-constant expression when the equation for this reaction is halved and then reversed?
  5. AP Chem

    At a particular temperature, Kp = 0.25 for the following reaction. N2O4(g) 2 NO2(g) (a) A flask containing only N2O4 at an initial pressure of 5.3 atm is allowed to reach equilibrium. Calculate the equilibrium partial pressures of …
  6. chem

    For the equilibrium reaction: CO(g)+H2O(g)<=>CO2(g)+H2(g) the Keq value at 690°C is 10.0. A mixture of 0.300 mol of CO, 0.300 mol of H2O, 0.500 mol of CO2 and 0.500 mol of H2 is placed in a 1.0 L flask. a)Write the Keq expression …
  7. CHEM

    For the equilibrium reaction Co(g)+H2O(g)<=>CO2(g)+H2(g) the Keq value at 690°C is 10.0. A mixture of 0.300 mol of CO, 0.300 mol of H2O, 0.500 mol of CO2 and 0.500 mol of H2 is placed in a 1.0 L flask. a) Write the Keq expression …
  8. Chemistry

    SO this is my first time doing this... lol i need help on an AP chemistry question for equilibrium. A 0.500 L tank contains 3.00 g of NO(g) at 750. K. The equilibrium constant for the reaction below at this temperature is 3.4 x 10 …
  9. Chemistry

    1. Write the balanced equation. Use ONLY this equation to reference how the reactions below will shift. Consider whether there is an addition, a removal, or no effect to the reaction. Co(H2O)6^2+ + 4Cl^- <--> CoCl4^2- + 6H2O …
  10. Chemistry Equilibrium

    1.15 g oh h2O (density 1.00 g/ml) is introduced into an empty 1.00 L container. The seled container is heated to 412 K and .150 moles of O2 (g) is present at equilibrium. A. Wrte the equilibrium expression for the reaction above. B. …

More Similar Questions