math

posted by .

Find the exanct real number of sec^-1√2, w/out calculator.

  • math -

    you know a 45-45-90 triangle has legs 1,1 and hypotenuse √2

    and so, ...

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Math

    1. Find y'(x) when xsecy - 3y sinx = 1 a) (3ycosx - sec y) / (xsec^2y - 3sinx) b) (3cosx - sec x) / (xsecytany - 3sinx) c) (3ycosx - sec y) / (xsecytany - 3sinx) d) (3ycosx - secytany) / xsec^2y - 3sinx) This is what I did: xsecy - …
  2. Math

    Find an equation of the line that bisects the obtuse angles formed by the lines with equations 3x-y=1 and x+y=-2. a. (3√2 +√10)x-(√10 + √2)y-2√10+√2=0 b. (3√2 - √10)x+(√10 - √2)y+2√10+√2=0 …
  3. algebra

    how do you find the square root of any number with long division and not a calculator?
  4. 8th grade algebra: radicals

    please help me solve these 1. 2√5/8 + 4√3/8 - 1/2√68 2. √4k-5 +1=8 (the radical sign goes over 4k-5) 3. (x+4)*2 /3 =8 4. Write the value of the discriminant of each equation. Then use it to decide how many different …
  5. Algebra

    Order the following numbers from least to greatest. √5, -0.1, (-5/3), 0.7, √2 a. 0.7, √2, (-5/3), √5, -0.1 b. √5, √2, 0.7, (-5/3), -0.1 c. (-5/3), -0.1, 0.7, √2, √5 ?
  6. 8th grade algebra

    Can you check my answers? 1. 3√20/√4 = 3√(5)(4)/2 = 3(2)√5/2 = 3√5 2. 4√15/√9 = 4√15/3 3. √12/√16 = √4(3)/4 = 2√3/4 = √3/2 4. √10/√5 = √2
  7. Algebra

    1. Simplify the expression: 4√18+5√32 A.45√2 B.32√2 C.116√2 D.9√50 2. Simplify the expression: 7√5-3√80 A.-5√5 B.-4√75 C.-5 D.4√-75 3. Simplify the expression: √21(√3+√14) …
  8. Algebra - Check My Work

    For Question 1-8 Simplify the Radical Expression *** - My Answer 1.√45 3√5*** 2.√180x^2 6x√5*** 3.√150x^3 k^4 5xk^2√6x*** 4.√21y * 5√49y 35y√21*** 5.(The square root sign applies …
  9. Math

    find the value of k in simplest form for which the larger root of x^2-5x+k=0 is √6+√11 * √3+√3+√11 * √3+√6+√3+√11 * √3-√6+√3+√11.
  10. Math

    I really need help with a quadratic question. So the problem is kx^2+[k+2]x-3=0 has roots which are real and positive. Find the possible values that k may have. The answer is -8+ √60<k<0 I get why they got -8+ √60 …

More Similar Questions