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What would the LCD be between x^2, 4x, and 6? Here is the problem: 1/x^2+3/4x-5/6

  • Math -

    Do it just like you would with numbers

    x^2 = x*x
    4x = 2*2*x
    6 = 2*3

    we will need x*x

    look at the second set of factors
    we will need 2*2*x , but we already have an x
    so far we need

    look at the last group
    we will need a 2*3
    but we already have the 2, so just include a 3

    LCD = 2*2*3*x*x = 12x^2

    notice that 12x^2 divides evenly by each of the other denominators

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