Math
posted by Mike .
What would the LCD be between x^2, 4x, and 6? Here is the problem: 1/x^2+3/4x5/6

Do it just like you would with numbers
x^2 = x*x
4x = 2*2*x
6 = 2*3
we will need x*x
look at the second set of factors
we will need 2*2*x , but we already have an x
so far we need
2*2*x*x
look at the last group
we will need a 2*3
but we already have the 2, so just include a 3
LCD = 2*2*3*x*x = 12x^2
notice that 12x^2 divides evenly by each of the other denominators