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What is the pH of a solution when 1ml of 0.10M NaOH is added to 100ml of buffer containing 0.1M acetic acid and 0.1M sodium acetate?

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    100 mL x 0.1M HAc = 10 mmoles.
    100 mL x 0.1M NaAc = 10 mmols.
    1 mL x 0.1M NaOH = 0.1 mmol.
    -----------------------
    ......HAc + OH^- ==> Ac^- + H2O
    I.....10.....0.......10
    add........0.1..............
    C...-0.1..-0.1.......+0.1
    E.....9.9...0........10.1

    Substitute the equilibrium values into the Henderson-Hasselbalch equation and solve for pH.

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