A business wants to give each of its employees a free ticket to the amusement park and has budgeted $1200 for tickets.
1. Write and solve an inequality to find the maximum number of 1-day, adult tickets that can be bought. When you round your answer, remember that there is no such thing as "part" of a ticket.
Inequality: _________
The maximum number of tickets that can be purchased: ___________
2. Suppose the business decides to purchase the tickets in groups of 10. Write and solve an inequality to find the maximum number tickets that can be purchased this way.
The maximum number of tickets that can be purchased: ___________ .
Which of the two deals is the better buy? .
you posted the same question before
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I had told you then that you had missing information, but you reposted it exactly the same way.
We would really like to help, but .......
The first part is ax is less than or equal to 1200. You substitute a as 41.49. you will get 28.92263195950831525668835640636. The maximum number is 28 because if u purchase 29, you will go over the budget.
1. To find the maximum number of 1-day, adult tickets that can be bought, we will set up an inequality based on the budget of $1200. Let's assume that the cost of each adult ticket is x dollars.
Inequality: x * N ≤ 1200
Here, N represents the number of tickets, and x represents the cost of one ticket. Since we want to find the maximum number of tickets, we want to maximize N.
Now, to solve the inequality, divide both sides by x:
N ≤ 1200 / x
Since we cannot have a fractional number of tickets, we need to round down to the nearest whole number. Therefore, the maximum number of tickets that can be purchased is the rounded down value of 1200 / x.
2. If the business decides to purchase the tickets in groups of 10, we will need to modify the previous inequality. Let's assume that the now discounted cost of each adult ticket is y dollars. The number of tickets purchased in groups of 10 will be denoted by M.
Inequality: y * M ≤ 1200
Here, M represents the number of ticket groups bought, and y represents the cost of one ticket in the group. Since we want to find the maximum number of tickets, we want to maximize M.
Now, to solve the inequality, divide both sides by y:
M ≤ 1200 / y
Since we cannot have a fractional number of groups, we need to round down to the nearest whole number. Therefore, the maximum number of tickets that can be purchased this way is the rounded down value of 1200 / y.
To compare the two deals, we need to evaluate which scenario gives more tickets. Compare the maximum number of tickets for each case, and the one with the higher value would be the better buy.