chemistry

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what mass of aluminum hydroxide needs to be consumed to neutralize 1.25L of stomach acid (HCl). Stomach acid has a pH of 2.2

  • chemistry -

    pH = -log(H^+)
    -2.2 = log(H^+) and
    (H^+) = 0.00631 M
    molsl H^+ = M x L = 0.00631 x 1.25 L = aboaut 0.008 but you need to that more accurately.
    Al(OH)3 + 3HCl = AlCl3 + 3H2O

    mols HCl = about 0.008
    Convert mols HCl to mols Al(OH)3 using the coefficients in the balanced equation. That will give you 0.008 x 1/3 = mols Al(OH)3.
    Convert that to grams. g = mols x molar mass.

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