PLEASE HELP!! DESPERATE!!! (MATH)
posted by Olivia .
The derivative of a function is f'(x)=x(x+2)(x5). Find the value of x at each point where f has a
(a) local maximum,
(b) local minimum, or
(c) point of inflection

Set f'=0
x=0,2,5 for f' to be zero.
maximum is when f" is negative
a) f"=(x+2)(x5)+x(x5)+(x(x+2)
at x=0, f"=10 so x=0 is max
b. f" at x=2
f"=(0+ 2(7) = positive, so at x=2, it is minimum
c. f" at x=5
f"=0+0+35 positive, local maximum
check my calcs 
oops, when f" is 35, local min
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