3/2y+2/y-1-2/y
3/(2y) + 4/(2y) - 2y/(2y) -4/(2y) = (3-2y)/(2y) or do you mean 3/(2y) +2/(y-1) -2/y ??? in that case LCD = [2y(y-1)] 3(y-1)/[2y(y-1)] +4y/[2y(y-1)]-4(y-1)/[2y(y-1)] or [3(y-1)+4y -4(y-1)]/[2y(y-1)] [3y+1]/[2y^2-2]
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