Pre-Calculus

posted by .

Is the period of f(x) = 2cos(3x - ð) 2ð/3?

• Pre-Calculus -

ð = pi

• Pre-Calculus -

one period is from x = 0 to x = 2 pi/3
so that the argument of the trig function changes by 2 pi

so the answer is 2 pi/3

Similar Questions

1. math

cosA= 5/9 find cos1/2A are you familiar with the half-angle formulas?
2. Pre-Calculus/Calculus

I am too embarassed to ask this Calculus (really pre-calculus) question in tutoring, because I know I should know. Is the inverse of f(x)=3x-1 actually f(x)=1/3x+1?
3. Pre-Calculus

how do u state the period of a function? for ex. f(x)=sin((1/2)x)
4. Pre-Calculus

Find the period and, where appropriate, the amplitude of the following function: y=2sin(x)
5. Pre-Cal

verify the identity sin x(1 - 2 cos^2 x + cos^4 x) = sin^5 x 1-2cos^2 x looks like 2cos^2x-1 its just backwards. I am not sure where to start.
6. Pre-Calculus

Can you show me how to find the rectangular equation: r=2cos(theta) + 3 sin (theta) All I need is an example to work off I was absent today from Pre-Calc and I have homework to do and no explanation with them-Please help with this …
7. Pre-Calculus

Find all solutions to the equation in the interval [0, 2pi) cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0 cos2(2x)-cos2x (2cos^2(2x)-1)-(2cos^2(x)-1) No idea what to do next.
8. pre-calculus

(tan^2x-9)(2cosx+1)=0 Find one period 4cos^2x-4cosx+1=0 find all angles and name 8 angles 7sin^2x-22sinx+3=0 find all angles and name 8 angles 2cos^2x-7cosx=-3 find one period sinx(2sinx+1)=0 find one period
9. Pre Calculus

Solve 2cos^2(2x)=1 I divided both sides by 2 and got this cos^2(2x)=1/2 But then I didn't know what to do after that... The part that has me stumped is that it's a cos^2(2x) not just a cos^2x. Any advice on what I should try next?
10. Math

Determine the solution of the equetion: 2cos x-1=0?

More Similar Questions

Post a New Question