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Is the period of f(x) = 2cos(3x - ð) 2ð/3?

  • Pre-Calculus -

    ð = pi

  • Pre-Calculus -

    one period is from x = 0 to x = 2 pi/3
    so that the argument of the trig function changes by 2 pi

    so the answer is 2 pi/3

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