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What is the final temperature (degrees celcius) of 1.36g of water with an initial temperature of 23.0degrees celcius after 6.420J of heat is added to it?

  • chem -

    m=dv
    mol C2H2=m/molar mass
    heat(q)= (delta H)(mol)

  • chem -

    q = [mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0

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