math

posted by .

if an object on earth is projected upward with an initial velocity of 32 feetper second, then its height after t seconds in given by h(t)=32t-16t^2

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math

    An object that is falling or vertically projected into the air has it height, in feet, above the ground given by the formula below, where s is the height in feet, Vo is the original velocity of the object, in feet per second, t is …
  2. algebra

    Please help me solve this: If an object is projected upward with an initial velocity of 112 feet per second from a height h of 128 feet, then its height t seconds after it is projected is defined by the equation h=-16t^2 + 112t + 128. …
  3. Math

    If an object is propelled upward from ground level with initial velocity of 55 feet per second, it's height h in feet t seconds later is given by the equation H=-16t^2+55t. after how many seconds does the object hit ground?
  4. math

    A diver on a platform 40 feet in height jumps upward with an initial velocity of 5ft/s. His height in h feet after t seconds is given by the function h=-16t^2+5t+50. a. What is his maximum height?
  5. Algebra 1

    a ball is thrown into the air with an upward velocity of 32 ft per second. Its height h in feet after t seconds is given by the function h(t)=-16t^2 +32t+6. How long does it take the ball to reach its maximum height?
  6. Math

    13.8.33 Question Help If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equation h=−16t squared + vt +​s, where …
  7. Math

    If an object is propelled upward fom a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equation he=−16t squared + vt + ​s, where h is in feet. If the …
  8. Math

    In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of …
  9. Maths

    object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of time in seconds after the ball was thrown. Also, …
  10. math

    if an object is projected upward from ground level with an initial velocity of 64 ft per sec,its height h in feet t seconds later is h=-16t+64t.after how many seconds is the height 48 ft.

More Similar Questions