chemistry
posted by Anonymous .
For the emission spectrum of Be3+, calculate the lowest wavenumber νˉ (in inverse meters) of light produced by electron transitions between n=2, n=3, and n=4.

w = wavelength
1/w = RZ^2(1/n1^2  1/n2^2)
R = 1.09737E7
Z = 4
n1^2= 3^2= 9
n2^2 = 4^2 = 16 
8.56*10^6
amar chauhan 
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