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Water flowing through a garden hose of diameter 2.72 cm fills a 25.0-L bucket in 1.10 min.
(a) What is the speed of the water leaving the end of the hose?

(b) A nozzle is now attached to the end of the hose. If the nozzle diameter is one-third the diameter of the hose, what is the speed of the water leaving the nozzle?

  • PHYSICS!!! -

    you get 25L/1.1min

    volume of lenght d of hose: diameter*length
    = PI*(.0272dm)^2(L)
    speed=L/time=25/(PI*.0272)^2 *1/1.10

    speed is in dm/minute, so to change that to m/s, divide by 10, and multiply by 60.

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