Post a New Question

math

posted by .

Find the absolute maximum value and the absolute minimum value, if any, of the following function.

f(x)=1/x^2+2x+8 on [-2,1]

  • math -

    f(-2) = 1/8
    f(1) = 1/11

    f' = 0 when x = -1
    f(-1) = 1/7
    f''(-1) < 0, so f(-1) is a max.

    So, max = 1/7, min = 1/11

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question