math
posted by Cindy .
Find the absolute maximum value and the absolute minimum value, if any, of the following function.
f(x)=1/x^2+2x+8 on [2,1]

f(2) = 1/8
f(1) = 1/11
f' = 0 when x = 1
f(1) = 1/7
f''(1) < 0, so f(1) is a max.
So, max = 1/7, min = 1/11