math
posted by Cindy .
Find the absolute maximum value and the absolute minimum value, if any, of the following function.
f(x)=1/x^2+2x+8 on [2,1]

math 
Steve
f(2) = 1/8
f(1) = 1/11
f' = 0 when x = 1
f(1) = 1/7
f''(1) < 0, so f(1) is a max.
So, max = 1/7, min = 1/11
Respond to this Question
Similar Questions

math
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x)=x^3+3x^21 on [3,1] 
Calculus (pleas help!!!)
Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter 1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum … 
Calculus (pleas help!!!)
Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter 1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute maximum … 
Math
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x)=x^3+3x^21 on [3,1] 
Math
Find the absolute maximum value and the absolute minimum value, if any, of the following function. f(x)=1/x^2+2x+8 on [2,1] 
Calculus
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.) f(x) = −x2 + 2x + 3 on [3, 6] maximum minimum 
Calculus
Find the absolute extrema of the function. (Round your answer to three decimal places.) f(x) = xex2 on [0,2] Absolute maximum value: at x = Absolute minimum value: at x = 
Calculus
Find the absolute extrema of the function. (Round your answer to three decimal places.) f(x) = xe^x2 on [0,2] Absolute maximum value: at x = Absolute minimum value: at x = 
Calculus
Find the absolute maximum and absolute minimum values of the function f(x)=x^3+6x^263x+4 on each of the indicated variables. Enter DNE for does not exist. (A) Interval = [8,0] Absolute maximum = Absolute minimum = (B) Interval = … 
Math(Calculus)
Im having a real difficult time solving this question. Find the absolute extrema of the function. h(x) = e^x^(2)  4 on [2,2] Absolute maximum value: at x = Absolute minimum value: at x =