Math

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2-sin^20/cos0 = sec0 + cos0

* 0 = Theta

  • Math -

    ok, so it is

    2 - sin^2 Ø/cosØ = secØ + cosØ ??

    2 - sin^2 Ø/cosØ = 1/cosØ + cosØ
    times cosØ
    2cosØ - sin^2 Ø = 1 + cos^2 Ø
    2cosØ = 1 + sin^2 Ø + cos^2 Ø
    2cosØ = 1+1
    cosØ = 1
    Ø = 0 , 2π or x = 0° , 360° , for the first period

    general solution
    x = 2kπ, where k is an integer

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