# Math

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2-sin^20/cos0 = sec0 + cos0

* 0 = Theta

• Math -

ok, so it is

2 - sin^2 Ø/cosØ = secØ + cosØ ??

2 - sin^2 Ø/cosØ = 1/cosØ + cosØ
times cosØ
2cosØ - sin^2 Ø = 1 + cos^2 Ø
2cosØ = 1 + sin^2 Ø + cos^2 Ø
2cosØ = 1+1
cosØ = 1
Ø = 0 , 2π or x = 0° , 360° , for the first period

general solution
x = 2kπ, where k is an integer

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