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Differentiate y=4^(3x^2)..
i need to know the calculation step..thanks for the help....

  • Math -

    What? You managed to do e^xlnx, and can't do this one?

    y' = ln4 4^(3x^2) (6x)
    ooh! Look, that's the same as ln(4^(6x)) 4^(3x^2)

    Looks like d/dx a^u = ln(a^u') a^u
    but probably better to leave it as lna a^u u'

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