posted by Anonymous .
A computer is reading data from a rotating CD-ROM. At a point that is 0.0382 m from the center of the disk, the centripetal acceleration is 118 m/s2. What is the centripetal acceleration at a point that is 0.0791 m from the center of the disc?
centripetal acceleration=I w^2 r so it is dependent linearly on R.
Acceleartion=118m/s^2 * (.0791/.0382)