Math

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(x-3) is a factor of x^3+ax^2+bx-3 but when divided by x+2 the remainder is 15
Solve for A and B

I know that A is 1 and B is -11, but I don't understand how to solve it

  • Math -

    the easiest way is synthetic division. ivide f(x) by x-3 to see that the remainder is

    9a+3b+24

    divide by x+2 and the remainder is

    4a - 2b - 11

    so, now you have two equations to solve

    3a+b+8 = 0
    4a - 2b - 11 = 15


    Looks like the solution above is correct

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