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a man walks 8km north and 5km in a direction east of north.find the distance from the starting point

  • math -

    8kmN moves (0,8)
    5km NE moves (3.5,3.5)

    add them up to get (3.5,11.5)

    distance is thus √(3.5^2 + 11.5^2) = 12.0

  • math -

    This is a pythagorean theorem problem:

    a^2 + b^2 = c^2

    You have two sides and you are going to solve for c.

  • math -


  • physics -

    1. A man walks 10km east and 20km south the displacement of the man from initial position
    2. In figure below R= 30, find x and Y respectively.

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