posted by etulan .
a man walks 8km north and 5km in a direction east of north.find the distance from the starting point
8kmN moves (0,8)
5km NE moves (3.5,3.5)
add them up to get (3.5,11.5)
distance is thus √(3.5^2 + 11.5^2) = 12.0
This is a pythagorean theorem problem:
a^2 + b^2 = c^2
You have two sides and you are going to solve for c.
1. A man walks 10km east and 20km south the displacement of the man from initial position
2. In figure below R= 30, find x and Y respectively.