A car decelerates from 30 m/s and rests at 6 seconds in a period of 5 m/s. How far did the car travel during that time.
To find the distance the car traveled during that time, we can use the equation:
distance = initial velocity * time + 1/2 * acceleration * time^2
In this case, the car decelerated from an initial velocity of 30 m/s to a final velocity of 5 m/s in a time of 6 seconds.
To find the acceleration, we can use the equation:
acceleration = (final velocity - initial velocity) / time
acceleration = (5 m/s - 30 m/s) / 6 s = -25 m/s / 6 s = -4.17 m/s^2
Now we can substitute the values into the distance equation:
distance = 30 m/s * 6 s + 1/2 * (-4.17 m/s^2) * (6 s)^2
distance = 180 m + 1/2 * -4.17 m/s^2 * 36 s^2
distance = 180 m + -74.94 m
distance = 105.06 m
Therefore, the car traveled a distance of 105.06 meters during that time.