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A particle moves in the xy plane with constant acceleration. At time zero, the particle is at x = 9 m,
y =6 m, and has velocity vo =(4.5 m/s)i + (−4 m/s)j. The acceleration is
given by a = (6 m/s2)i + (1 m/s2)j.

What is the magnitude of the displacement from the origin (x = 0 m, y = 0 m) after 8.5 s?
Answer in units of m

  • physics -

    d= dinitial + vi *t+1/2 a t^2

    Idont understand your question here. Just put in dinitial, vi, and a, and do it. d will be a vector

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