Chemistry

posted by .

My question is 'what does the area under the curve represent?' it's a Maxwell-Boltzmann curve.

My first idea was the number of particles but that's just what the y axis says and surely that wouldn't just mean under the curve.

My second idea was to write that anything before the activation energy line would not have sufficient energy and anything after would.

Any help would be much appreciated.

  • Chemistry -

    There is a number of different horizontal axis versions of the Maxwell-Boltzmann probability funcitons. Most often, it is Energy or speed of molecules.

    The area underneath must be total energy below some certain energy, or speed. So at the activation energy point, the area would represent the quantity of energy in the material that is below the threshold for activation. The area left to the right, is the amount of energy in the material that meets the threshold or is above it.

    Consider water evaporating. The curve for it, consider the horizontal axis to be speed of molecules (or energy, or temperature). Draw a vertical line on the tail, we will call that the speed for the water molecules sufficently great to escape the surface of water, and become gas. So the area above, is the amount of water energy lost in evaporation, thus, the average temperature has to go down in the water remaining (which we observe).

    Cumulative area: total energy below some point.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. AP Statistics

    A certain density curve looks like an interverted letter V. The first segment goes fro the point (0,0.6) to the point (0.5,1.4). The segment goes from (0.5.1.44) to (1,0.6). (a) Sketch the curve. Verify that the area under the curve …
  2. Stat

    Remeber that it is areas under a density curve, not the height of the curve, that give proportions in a distribuiton. To illustrate this, sketch a density curve that has its peak at 0 on the horizontal axis but ahs greater area within …
  3. Calculus

    Integrals: When we solve for area under a curve, we must consider when the curve is under the axis. We would have to split the integral using the zeros that intersect with the axis. Would this be for all integrals?
  4. calculus, volume , application of integration

    show steps for the following: Consider the curve f(x)=x^4 between x = -1 and x = 4. a)What is the volume obtained by revolving the area under the curve around the x-axis?
  5. math-plz help

    Consider the curve f(x)=x^4 between x = -1 and x = 4. a)What is the volume obtained by revolving the area under the curve around the x-axis?
  6. Calculus ll - Improper Integrals

    Find the area of the curve y = 1/(x^3) from x = 1 to x = t and evaluate it for t = 10, 100, and 1000. Then find the the total area under this curve for x ≥ 1. I'm not sure how to do the last part of question ("find the the total …
  7. Math help

    We have no ideal on how to start this problem, we have look for it on the charts, did not see. Please help Consider the following. (Give your answers correct to two decimal places.) (a) Find the standard score (z) such that the area …
  8. Math help

    We have no ideal on how to start this problem, we have look for it on the charts, did not see. Please help Consider the following. (Give your answers correct to two decimal places.) (a) Find the standard score (z) such that the area …
  9. Math help

    Can someone give me a heads up on how to even start this problem.. Consider the following. (Give your answers correct to two decimal places.) (a) Find the standard score (z) such that the area above the mean and below z under the normal …
  10. Calculus

    Find the area cut off by x+y=3 from xy=2. I have proceeded as under: y=x/2. Substituting this value we get x+x/2=3 Or x+x/2-3=0 Or x^2-3x+2=0 Or (x-1)(x-2)=0, hence x=1 and x=2 are the points of intersection of the curve xy=2 and the …

More Similar Questions