Physics
posted by Claire .
The cheetah can reach a top speed of 114 km/h (71 mi/h). While chasing its prey in a short sprint, a cheetah starts from rest and runs 46 m in a straight line, reaching a final speed of 83 km/h.
(a) Determine the cheetah's average acceleration during the short sprint.
(b) Find its displacement at t = 3.0 s. (Assume the cheetah maintains a constant acceleration throughout the sprint.)

Vfinal = 83 km/h = 23.06 m/s
(a) Vfinal^2 = 2*a*X, so
a = Vfinal^2/(2*X)
a = 5.78 m/s^2
(b)At t = 3.0
V = a*t = 17.33 m/s
x = (1/2)a*t^2 = 26.0 m
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