With an average acceleration of −1.6 m/s^2,
how long will it take a cyclist to bring a bicycle
with an initial speed of 13.3 m/s to a complete
stop?
Answer in units of s
(A)Acceleration = -1.6 m/s
Vi = 13.3 m/s
Vf = 0
T(time) = ?
T = Vf-Vi/A
T = 0-13.3/-1.6
T = 8.3125 s
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To solve this problem, we can use the kinematic equation:
v_final = v_initial + (acceleration)(time)
where:
v_final = final velocity (0 m/s, since the bicycle comes to a complete stop)
v_initial = initial velocity (13.3 m/s)
acceleration = average acceleration (-1.6 m/s^2)
time = unknown (what we're solving for)
Rearranging the equation to solve for time:
0 = 13.3 + (-1.6)(time)
Simplifying the equation:
-13.3 = -1.6(time)
Dividing both sides of the equation by -1.6:
time = 13.3 / 1.6
Calculating the time:
time ≈ 8.3125 s
Therefore, it will take approximately 8.3125 seconds for the cyclist to bring the bicycle to a complete stop.