posted by Lily
when 10.0 ml of a .20 M Cu (NO3)2 solution is mixed with 15.0 mL of 0.20M NaOH, what is the theoretical yield (grams) of copper (II) hydroxide?
Write and balance the equation.
Convert Cu(NO3)2 to mols. mol = M x L = ?
Using the coefficients in the balanced equation convert mols Cu(NO3)2 to mols Cu(OH)2.
Now convert mols Cu(OH)2 to grams. g = mols x molar mass. This is the theoretical yield.
what's the balanced equation?
Cu(NO3)2 + 2NaOH ==> Cu(OH)2 + 2HNO3