Chemistry

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when 10.0 ml of a .20 M Cu (NO3)2 solution is mixed with 15.0 mL of 0.20M NaOH, what is the theoretical yield (grams) of copper (II) hydroxide?

  • Chemistry -

    Write and balance the equation.
    Convert Cu(NO3)2 to mols. mol = M x L = ?
    Using the coefficients in the balanced equation convert mols Cu(NO3)2 to mols Cu(OH)2.
    Now convert mols Cu(OH)2 to grams. g = mols x molar mass. This is the theoretical yield.

  • Chemistry -

    what's the balanced equation?

  • Chemistry -

    Cu(NO3)2 + 2NaOH ==> Cu(OH)2 + 2HNO3

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