# Chemistry

posted by Lily

when 10.0 ml of a .20 M Cu (NO3)2 solution is mixed with 15.0 mL of 0.20M NaOH, what is the theoretical yield (grams) of copper (II) hydroxide?

1. DrBob222

Write and balance the equation.
Convert Cu(NO3)2 to mols. mol = M x L = ?
Using the coefficients in the balanced equation convert mols Cu(NO3)2 to mols Cu(OH)2.
Now convert mols Cu(OH)2 to grams. g = mols x molar mass. This is the theoretical yield.

2. Lily

what's the balanced equation?

3. DrBob222

Cu(NO3)2 + 2NaOH ==> Cu(OH)2 + 2HNO3

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