Chemistry

posted by .

How would I find the percent of water lost in alum after it has dried for a week?
Wet Alum = 13.44g
Dry Alum = 11.28g

• Chemistry -

I believe you would subtract the dry weight of the alum from the wet alum weight, then divide that answer by the original weight of wet alum:

13.44g(wet) - 11.28g (dry) = 2.16g of water that was lost.

2.16g H20/ 13.44g wet alum =0.1607 X 100 = 16.07% H20 lost

Hope this helps :)

Similar Questions

1. Chemistry

I conducted the synthesis of an Alum experiment in my lab last week and I'm working on my report. I'm almost done expect I don't know how one could increase the yield of the product (alum crystal)?
2. Chemistry

Alum is a hydrated compound containing 45.5% water. How many moles of water are contained in one mole of this hydrate. Data for alum M= 474 g∙mol-1
3. chemisty

what will be the mass of angydrous Alum left over if one starts with 100.00 g of hydrated Alum?
4. Chemistry

Calculate the percent yield of alum if you obtained 75.0 g of potassium alum from 5.00 g Al.
5. Chemistry

I had a 1.094g of mystery Alum. "AB(SO4)c. dH2O" (I assume that that the Alum is KAl(SO4)2-12H2O but we don't know A B c or d, we do know that mass percent of water is 51.9) After processing the alum (Ba(NO3)2 and HNO3 through a gooch …
6. AP Chemistry

1. If alum is heated at first too strongly causing it to splatter out of the crucible what effect will this have on the determination of the water hydration?
7. Chemistry 211

Which of the following statements is a reasonable explanation for why a percent yield may be less than 100% for the synthesis of the alum, select all that apply. a) The aluminium foil did not completely react b) Some alum sample remained …
8. chem/science

A piece of an aluminum can was cut into small pieces. Then 0.422 g of the chips from the can was used to prepare potassium alum according to the procedure we used. Calculate the theoretical yield (in g) of potassium alum that could …
9. chemistry

A piece of an aluminum can was cut into small pieces. Then 0.422 g of the chips from the can was used to prepare potassium alum according to the procedure we used. Calculate the theoretical yield (in g) of potassium alum that could …
10. Chemistry lab

1)Why is it necessary to heat the alum until its mass does not change by more than 2mg?

More Similar Questions