a horse is $5 a cow is $3 & chickens r $.50 ea. now buy 100 animals 4 exactly $100
English please!
You basically aren't going to meet your budget dude...
To solve this problem, we need to come up with a combination of horses, cows, and chickens that will add up to 100 animals and cost exactly $100.
Let's assume:
- Number of horses = H
- Number of cows = C
- Number of chickens = 100 - H - C
Given the prices:
- The cost of horses = $5 each
- The cost of cows = $3 each
- The cost of chickens = $0.50 each
We can set up the equation to represent the total cost:
5H + 3C + 0.50(100 - H - C) = 100
Now, let's simplify and solve the equation step-by-step:
5H + 3C + 50 - 0.50H - 0.50C = 100
4.50H + 2.50C = 50
To make it easier to work with, let's divide both sides of the equation by 0.50:
9H + 5C = 100
Now, we need to find the values of H and C that satisfy this equation.
One possible approach to find the solution is through trial and error. We can start by assuming different values for H and calculate the corresponding values of C:
If H = 0, then 5C = 100, so C = 20. But this doesn't satisfy the equation since the total number of animals would be 100 + 20 = 120.
If H = 1, then 9 + 5C = 100. Subtracting 9 from both sides, we get 5C = 91. This equation doesn't yield whole numbers for C, so this is not a valid solution.
If H = 2, then 18 + 5C = 100. Subtracting 18 from both sides, we get 5C = 82. Again, this equation doesn't yield whole numbers for C, so this is not a valid solution.
If H = 3, then 27 + 5C = 100. Subtracting 27 from both sides, we get 5C = 73. This equation doesn't yield whole numbers for C, so this is not a valid solution.
If H = 4, then 36 + 5C = 100. Subtracting 36 from both sides, we get 5C = 64. This equation doesn't yield whole numbers for C, so this is not a valid solution.
If H = 5, then 45 + 5C = 100. Subtracting 45 from both sides, we get 5C = 55. This equation doesn't yield whole numbers for C, so this is not a valid solution.
Continuing this process, we can find that H = 6 and C = 10 is a valid solution:
54 + 50 = 100.
Therefore, if you buy 6 horses, 10 cows, and 84 chickens, you will have exactly 100 animals, and the total cost will be $100.