What will be the perimeter of a rectangle it's length is 3 times it's breadth and he root of the diagonal is 8* root over 10cm ?????
w = 3b
d = 8√10
w^2 + b^2 = d^2
(3b)^2 + b^2 = 64*10
10b^2 = 640
b^2 = 64
b = 8
so, w = 24
so, p = 2(8+24) = 64