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#Still Don't Understand how to solve this..

  • Algebra2 -

    just like the one with x^1/2,
    I think you meant to type

    6x^2/3 - 5x^1/3 - 6 = 0
    can't do it if it is as you typed it.

    let u = x^1/3
    then you have
    6u^2 - 5u - 6 = 0
    (3u+2)(2u-3) = 0
    u = -2/3 or 3/2

    so, x^1/3 = -2/3 or 3/2
    x = -8/27 or 27/8

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