Algebra2
posted by Unknown .
Help?
1.6x^6/35x^1/36=0
#Still Don't Understand how to solve this..

just like the one with x^1/2,
I think you meant to type
6x^2/3  5x^1/3  6 = 0
can't do it if it is as you typed it.
let u = x^1/3
then you have
6u^2  5u  6 = 0
(3u+2)(2u3) = 0
u = 2/3 or 3/2
so, x^1/3 = 2/3 or 3/2
x = 8/27 or 27/8
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