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geometry

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I"m stuck on this question
"Rays PQ and QR ae perpendicular.Point S lies in the interior of angle PQR.If angle PQS!=4+7a and angle SQR=9+4a,find angle PQS and angle SQR.
PLEASE HELP!!!!

  • geometry -

    4 + 7 a + 9 + 4 a = 90 degrees
    13 + 11 a = 90
    11 a = 77
    a = 7

    PQS = 4 + 49
    SQR = 9 + 28

  • geometry -

    Thank you so much!!!!!

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