How to make all sums the same in a 9 square box in every direction? Top row has a 89, and a 41
To make the sums the same in every direction in a 9 square box, including the top row with numbers 89 and 41, you need to distribute the remaining numbers in a way that ensures each row, column, and diagonal add up to the same sum.
Let's assume we want the sum of each row, column, and diagonal to be "x".
The sum of all numbers in the box would be 9x since there are 9 numbers in total.
Since the top row already has two numbers, 89 and 41, the sum of the remaining seven numbers in the box should be 7x - (89 + 41).
Now, you have to distribute the remaining numbers in a way that satisfies this equation:
7x - (89 + 41) = 7x - 130
To make the sums the same in every direction, you need to place the remaining seven numbers in such a way that each row, column, and diagonal have a sum of 7x - 130.
It's important to note that there are multiple ways to distribute the numbers to achieve the desired sum. You can experiment with different combinations to find the solution that works best for you.