Math: Story Problem
posted by Losa .
A buffetstyle restaurant has 18 tables that seat 23 people each. A church group of 401 has rented the restaurant for a banquet. If the pastor of another church, his wife, and their nine children come as invited guests, what is the least number of people can sit at any one table? Please help Ms.Sue and Writeacher.

401 + 11 = 412
412 / 18 = 22.9 
Oh Ms.Sue! That almost look like the story problem that was an example in the previous page in my math book! I should follow that. Thank you very much Ms.Sue!

Sorry for that Ms.Sue. But seriously thank you!

You're very welcome. Losa. :)

What is your answer?