Math: Story Problem
posted by Losa .
A buffet-style restaurant has 18 tables that seat 23 people each. A church group of 401 has rented the restaurant for a banquet. If the pastor of another church, his wife, and their nine children come as invited guests, what is the least number of people can sit at any one table?- Please help Ms.Sue and Writeacher.
401 + 11 = 412
412 / 18 = 22.9
Oh Ms.Sue! That almost look like the story problem that was an example in the previous page in my math book! I should follow that. Thank you very much Ms.Sue!
Sorry for that Ms.Sue. But seriously thank you!
You're very welcome. Losa. :-)
What is your answer?