# Math

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(a^6 x a^6)^k = (a^3)^(k+5)

Solve for k.
a. 3/2
b. 5/3
c. 2
d. 3
e. 5

I think when simplified its (a^12)^k = (a^3)^(k+5)
but i don't know how to get k from here. How do you solve for these kind of exponents?

• Math -

a^12 = (a^3)^4, so

(a^3)^(4k) = (a^3)^(k+5), so
4k = k+5
k = 5/3

• Math -

Thank you so much :D

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