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Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCL(aq)=>ZnCl2(aq)+H2(g). How many mm of 1.50M HCL(aq) are required to react with 9.05 g of ZN?

  • chemistry -

    Zn + 2HCl ==> ZnCl2 + H2

    mols Zn = grams/atomic mass Zn
    Convert mols Zn to mols HCl using the coefficients in the balanced equation.
    Then convert mols HCl to volume using M = mols/L. You know mols and M, solv for L and convert to mL.
    By the way, that is mL and not mm.

  • chemistry -

    92.28

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