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the area of a rectangle is 175 and the length is 1 and a half times bigger than the width. find the width L x W = Area L = 1.5W 1.5W x W = 175 or 1.5W^2 = 175 W^2 = =116.666 making W = 10.80... and L = 16.20... 10.80... x 16.20... … 
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substitution method 7x +9y= 19 x=255y ___________ 7(255y)+9=19 17535 +9=19 175 175 _______________ 26y= 156 y=6 substitute for x x=255y x=255(6) x=2530 x=5 now substitute 7x+9y=19 7(5)+ 9(6)=19 30+56=19 19=19 his part … 
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Can you please tell me what is the Percentage of 250,800.00/2,175,000 I have 11.53% is this correct. 
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The perimeter of a rectangular deck is 175 feet. The length of the deck, L, is 6 feet longer than 2 times the width, W. Which system of equations can be solved to determine the length and width, in feet, of the deck? 
variation! Steve pls check my solution!!!
what if d maths is done like dx? L=km/h When L=40,m=175,h=286, (skipping the units) 40=k(175)/ 286 K=286(40)/175=2288/35 L=2288/35=250/50 L=114400/8750 L =13.1m