Math
posted by Mayank .
Solve:
3x + 7y + 5= 0
4x  3y  8 = 0
Find p; if:
px + y  1= 0

3X+7Y+5=0.,..,..,.,..(1)
4X3Y8=0..,,..,.,...,..(2)
From (1) x=(57y)/3..,..,..(3) put into equ (2) for x ; (2028y)/38=0 ; y=31/28=1.1 put into equ 3 for y
x=(57.7)/3=4.2
4.2p +1.11=0 ; p=0.1/4.2
p=0.024 
first times 3 > 9x + 21y = 15
2nd times 7 > 28x  21y = 56
add them
37x = 41
x = 41/37
sub into 1st:
3(41/37) + 7y = 5
7y = 5  123/37 = 308/37
y = 44/37
then if px + y = 1
p(41/37)  44/37 = 1
p = (1 + 44/37)(37/41) = 81/41
I verified the above answers, they satisfy the original equations. 
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