math
posted by ted .
How to fully factor X^38.
pls help

The difference of cubes formula is:
x^3 − y^3 = (x − y)*(x^2 + xy + y^2)
Your x is x in this case and y = 8 (2^3).
So you get:
x^3  2^3 = (x  2)*(x^2 + 2x + 4).
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